Kenya Airways KQ7085 Flight Status Today

Domestic flight Kenya Airways KQ7085 takes off from New York (JFK) United States to Indianapolis (IND) United States. It's operated by Kenya Airways. The plane leaves John F. Kennedy International Airport at 17:59 America/New_York. The flight is expected to land at Indianapolis International Airport at 20:27 America/Indiana/Indianapolis. The flight will last about 2 hours 28 minutes.

KQ7085 - KQA7085 Kenya Airways (KQ)
JFK New York United States
Flight JFK to IND
IND Indianapolis United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 17:59
4 A9
Arrival Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 20:27
None A10
KQ7085 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 28 minutes
  • Flight Distance: 1069 kms / 664 miles
Airline
  • Kenya Airways
  • IATA: KQ
  • ICAO: KQA
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Indiana/Indianapolis
  • Current Time in New York: Wednesday 2025-12-31 14:52 PM
  • Current Time in Indianapolis: Wednesday 2025-12-31 14:52 PM

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Kenya Airways Flight KQ7085 FAQs

What is the scheduled flight duration for Kenya Airways KQ7085 flight?

On average, nonstop flight takes 2 hour(s) 28 minutes, with the flight distance of 1069 km (664 miles).

What type of aircraft is used for the Kenya Airways KQ7085 flight?

All Kenya Airways KQ7085 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

How many Kenya Airways KQ7085 flights are operated a week?

1 flights per week. The Flight Kenya Airways KQ7085 is operated on Saturday.