Kenya Airways KQ7080 Flight Status Today

Domestic flight Kenya Airways KQ7080 takes off from New York (JFK) United States to Boston (BOS) United States. It's operated by Kenya Airways. The plane leaves John F. Kennedy International Airport at 17:20 America/New_York. The flight is expected to land at Logan International Airport at 18:43 America/New_York. The flight will last about 1 hours 3 minutes.

KQ7080 - KQA7080 Kenya Airways (KQ)
JFK New York United States
Flight JFK to BOS
BOS Boston United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 17:20
4 A17
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 18:43
A A3
KQ7080 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 3 minutes
  • Flight Distance: 300 kms / 186 miles
Airline
  • Kenya Airways
  • IATA: KQ
  • ICAO: KQA
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Tuesday 2026-02-10 01:03 AM
  • Current Time in Boston: Tuesday 2026-02-10 01:03 AM

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Kenya Airways Flight KQ7080 FAQs

What is the scheduled flight duration for Kenya Airways KQ7080 flight?

On average, nonstop flight takes 1 hour(s) 3 minutes, with the flight distance of 300 km (186 miles).

What type of aircraft is used for the Kenya Airways KQ7080 flight?

All Kenya Airways KQ7080 flights are operated using Embraer 175 aircraft.

Which terminal the flight Kenya Airways KQ7080 is arriving at?

Flight Kenya Airways KQ7080 arrives in Logan International Airport at Terminal A.

How many Kenya Airways KQ7080 flights are operated a week?

1 flights per week. The Flight Kenya Airways KQ7080 is operated on Saturday.