Kenya Airways KQ7070 Flight Status Today

Domestic flight Kenya Airways KQ7070 takes off from New York (JFK) United States to Syracuse (SYR) United States. It's operated by Kenya Airways. The plane leaves John F. Kennedy International Airport at 19:35 America/New_York. The flight is expected to land at Hancock International Airport at 21:08 America/New_York. The flight will last about 1 hours 18 minutes.

KQ7070 - KQA7070 Kenya Airways (KQ)
JFK New York United States
Flight JFK to SYR
SYR Syracuse United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 19:35
4 A9
Arrival Hancock International Airport
IATA: SYRICAO: KSYR
Scheduled 21:08
B 24
KQ7070 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 18 minutes
  • Flight Distance: 336 kms / 208 miles
Airline
  • Kenya Airways
  • IATA: KQ
  • ICAO: KQA
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Saturday 2026-02-28 00:05 AM
  • Current Time in Syracuse: Saturday 2026-02-28 00:05 AM

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Kenya Airways Flight KQ7070 FAQs

What is the scheduled flight duration for Kenya Airways KQ7070 flight?

On average, nonstop flight takes 1 hour(s) 18 minutes, with the flight distance of 336 km (208 miles).

What type of aircraft is used for the Kenya Airways KQ7070 flight?

All Kenya Airways KQ7070 flights are operated using Embraer 175 aircraft.

Which terminal the flight Kenya Airways KQ7070 is arriving at?

Flight Kenya Airways KQ7070 arrives in Hancock International Airport at Terminal B.

How many Kenya Airways KQ7070 flights are operated a week?

1 flights per week. The Flight Kenya Airways KQ7070 is operated on Monday.