Kenya Airways KQ7069 Flight Status Today

Domestic flight Kenya Airways KQ7069 takes off from Syracuse (SYR) United States to New York (JFK) United States. It's operated by Kenya Airways. The plane leaves Hancock International Airport at 05:25 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 07:00 America/New_York. The flight will last about 1 hours 35 minutes.

KQ7069 - KQA7069 Kenya Airways (KQ)
SYR Syracuse United States
Flight SYR to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure Hancock International Airport
IATA: SYRICAO: KSYR
Scheduled 05:25
B 25
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 07:00
4 A12
KQ7069 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 336 kms / 208 miles
Airline
  • Kenya Airways
  • IATA: KQ
  • ICAO: KQA
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Syracuse: Sunday 2026-02-08 06:41 AM
  • Current Time in New York: Sunday 2026-02-08 06:41 AM

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Kenya Airways Flight KQ7069 FAQs

What is the scheduled flight duration for Kenya Airways KQ7069 flight?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 336 km (208 miles).

What type of aircraft is used for the Kenya Airways KQ7069 flight?

All Kenya Airways KQ7069 flights are operated using Embraer 175 aircraft.

Which terminal the flight Kenya Airways KQ7069 is arriving at?

Flight Kenya Airways KQ7069 arrives in John F. Kennedy International Airport at Terminal 4.

How many Kenya Airways KQ7069 flights are operated a week?

1 flights per week. The Flight Kenya Airways KQ7069 is operated on Monday.