Kenya Airways KQ7008 Flight Status Today

Domestic flight Kenya Airways KQ7008 takes off from New York (JFK) United States to Denver (DEN) United States. It's operated by Kenya Airways. The plane leaves John F. Kennedy International Airport at 08:30 America/New_York. The flight is expected to land at Denver International Airport at 11:10 America/Denver. The flight will last about 4 hours 40 minutes.

KQ7008 - KQA7008 Kenya Airways (KQ)
JFK New York United States
Flight JFK to DEN
DEN Denver United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 08:30
4 B47
Arrival Denver International Airport
IATA: DENICAO: KDEN
Scheduled 11:10
None A50
KQ7008 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 hours 40 minutes
  • Flight Distance: 2616 kms / 1625 miles
Airline
  • Kenya Airways
  • IATA: KQ
  • ICAO: KQA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-900 Passenger (Scimitar Winglets)
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Denver
  • Current Time in New York: Friday 2026-05-01 23:29 PM
  • Current Time in Denver: Friday 2026-05-01 21:29 PM

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El Al LY4273
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Kenya Airways Flight KQ7008 FAQs

What is the scheduled flight duration for Kenya Airways KQ7008 flight?

On average, nonstop flight takes 4 hour(s) 40 minutes, with the flight distance of 2616 km (1625 miles).

What type of aircraft is used for the Kenya Airways KQ7008 flight?

All Kenya Airways KQ7008 flights are operated using Boeing 737-900 Passenger (Scimitar Winglets) aircraft.

How many Kenya Airways KQ7008 flights are operated a week?

6 flights per week. The Flight Kenya Airways KQ7008 is operated on Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday.