Kenya Airways KQ4614 Flight Status Today

Domestic flight Kenya Airways KQ4614 takes off from Johannesburg (JNB) South Africa to George (GRJ) South Africa. It's operated by Kenya Airways. The plane leaves O.R. Tambo International Airport at 09:45 Africa/Johannesburg. The flight is expected to land at George Airport at 11:40 Africa/Johannesburg. The flight will last about 1 hours 55 minutes.

KQ4614 - KQA4614 Kenya Airways (KQ)
JNB Johannesburg South Africa
Flight JNB to GRJ
GRJ George South Africa
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 09-July-2021
Departure O.R. Tambo International Airport
IATA: JNBICAO: FAOR
Scheduled 09:45
B None
Arrival George Airport
IATA: GRJICAO: FAGG
Scheduled 11:40
None None
KQ4614 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 55 minutes
  • Flight Distance: 1038 kms / 645 miles
Airline
  • Kenya Airways
  • IATA: KQ
  • ICAO: KQA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 189
  • Freight capacity: 17.8 tons
  • Passenger classes: Economy, Business Class, Shuttle
More Detail
  • Aircraft: Boeing 737-800 Passenger
  • Callsign: KQA4614
  • Departure Timezone: Africa/Johannesburg
  • Arrival Timezone: Africa/Johannesburg
  • Current Time in Johannesburg: Sunday 2026-03-01 20:14 PM
  • Current Time in George: Sunday 2026-03-01 20:14 PM

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Kenya Airways Flight KQ4614 FAQs

What is the scheduled flight duration for Kenya Airways KQ4614 flight?

On average, nonstop flight takes 1 hour(s) 55 minutes, with the flight distance of 1038 km (645 miles).

What type of aircraft is used for the Kenya Airways KQ4614 flight?

All Kenya Airways KQ4614 flights are operated using Boeing 737-800 Passenger aircraft.