KLM KL7438 Flight Status Today

Domestic flight KLM KL7438 takes off from Columbus (CMH) United States to Detroit (DTW) United States. It's operated by KLM. The plane leaves John Glenn Columbus International Airport at 18:04 America/New_York. The flight is expected to land at Detroit Metropolitan Wayne County Airport at 19:15 America/New_York. The flight will last about 1 hours 11 minutes.

KL7438 - KLM7438 KLM (KL)
CMH Columbus United States
Flight CMH to DTW
DTW Detroit United States
Contact Airlines It may not operate on the date requested
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 18:04
None C53
Arrival Detroit Metropolitan Wayne County Airport
IATA: DTWICAO: KDTW
Scheduled 19:15
M B15
KL7438 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 11 minutes
  • Flight Distance: 249 kms / 154 miles
Airline
  • KLM
  • IATA: KL
  • ICAO: KLM
  • Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: First Class, Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: KLM7438
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Sunday 2026-02-08 23:32 PM
  • Current Time in Detroit: Sunday 2026-02-08 23:32 PM

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KLM Flight KL7438 FAQs

What is the scheduled flight duration for KLM KL7438 flight?

On average, nonstop flight takes 1 hour(s) 11 minutes, with the flight distance of 249 km (154 miles).

What type of aircraft is used for the KLM KL7438 flight?

All KLM KL7438 flights are operated using Embraer 175 aircraft.

Which terminal the flight KLM KL7438 is arriving at?

Flight KLM KL7438 arrives in Detroit Metropolitan Wayne County Airport at Terminal M.

How many KLM KL7438 flights are operated a week?

6 flights per week. The Flight KLM KL7438 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.