Korean Air KE7638 Flight Status Today

Domestic flight Korean Air KE7638 takes off from Boston (BOS) United States to New York (JFK) United States. It's operated by Korean Air. The plane leaves Logan International Airport at 17:00 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 18:41 America/New_York. The flight will last about 1 hours 41 minutes.

KE7638 - KAL7638 Korean Air (KE)
BOS Boston United States
Flight BOS to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 17:00
A A11
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 18:41
4 A17
KE7638 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 41 minutes
  • Flight Distance: 300 kms / 186 miles
Airline
  • Korean Air
  • IATA: KE
  • ICAO: KAL
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Wednesday 2025-12-31 09:10 AM
  • Current Time in New York: Wednesday 2025-12-31 09:10 AM

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Korean Air Flight KE7638 FAQs

What is the scheduled flight duration for Korean Air KE7638 flight?

On average, nonstop flight takes 1 hour(s) 41 minutes, with the flight distance of 300 km (186 miles).

What type of aircraft is used for the Korean Air KE7638 flight?

All Korean Air KE7638 flights are operated using Embraer 175 aircraft.

Which terminal the flight Korean Air KE7638 is arriving at?

Flight Korean Air KE7638 arrives in John F. Kennedy International Airport at Terminal 4.

How many Korean Air KE7638 flights are operated a week?

1 flights per week. The Flight Korean Air KE7638 is operated on Tuesday.