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Kalitta Charters K948 Flight Status Today
Domestic flight Kalitta Charters K948 takes off from Milwaukee (MKE) United States to Sarasota (SRQ) United States. It's operated by Kalitta Charters. The plane leaves General Mitchell International Airport at 22:43 America/Chicago. The flight is expected to land at Sarasota Bradenton International Airport at 02:56 America/New_York. The flight will last about 3 hours 11 minutes.
K948 - KFS48
Kalitta Charters (K9)
MKE
Milwaukee United States
SRQ
Sarasota United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 05-January-2021
K948 Detail
- Type: Domestic Flight
- Flight Duration: 3 hours 11 minutes
- Flight Distance: 1793 kms / 1114 miles
Airline
- Kalitta Charters
- IATA: K9
- ICAO: KFS
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: LJ35
- Callsign: KFS48
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Milwaukee: Wednesday 2026-03-04 07:49 AM
- Current Time in Sarasota: Wednesday 2026-03-04 08:49 AM
Flight routes similar to Kalitta Charters K948
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
DL5892 Delta |
04/03/2026 11:00 |
2 hours 30 minutes 14:30 |
Kalitta Charters Flight K948 FAQs
What is the scheduled flight duration for Kalitta Charters K948 flight?
On average, nonstop flight takes 3 hour(s) 11 minutes, with the flight distance of 1793 km (1114 miles).
What type of aircraft is used for the Kalitta Charters K948 flight?
All Kalitta Charters K948 flights are operated using LJ35 aircraft.
