Kalitta Air K49907 Flight Status Today

Domestic flight Kalitta Air K49907 takes off from New York (JFK) United States to Chicago (ORD) United States. It's operated by Kalitta Air. The plane leaves John F. Kennedy International Airport at 20:05 America/New_York. The flight is expected to land at O'Hare International Airport at 22:05 America/Chicago. The flight will last about 1 hours 58 minutes.

K49907 - CKS9907 Kalitta Air (K4)
JFK New York United States
Flight JFK to ORD
ORD Chicago United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 11-June-2021
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:05
None None
Arrival O'Hare International Airport
IATA: ORDICAO: KORD
Scheduled 22:05
None None
K49907 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 58 minutes
  • Flight Distance: 1190 kms / 739 miles
Airline
  • Kalitta Air
  • IATA: K4
  • ICAO: CKS
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 747-400 Passenger
  • Callsign: F-UTNU2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in New York: Saturday 2026-02-07 02:44 AM
  • Current Time in Chicago: Saturday 2026-02-07 01:44 AM

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Kalitta Air Flight K49907 FAQs

What is the scheduled flight duration for Kalitta Air K49907 flight?

On average, nonstop flight takes 1 hour(s) 58 minutes, with the flight distance of 1190 km (739 miles).

What type of aircraft is used for the Kalitta Air K49907 flight?

All Kalitta Air K49907 flights are operated using Boeing 747-400 Passenger aircraft.