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Kalitta Air K49873 flight status now
K49873 - CKS9873
Kalitta Air (K4)
JFK
New York United States
OSC
Oscoda United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on
K49873 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 28 minutes
- Flight Distance: 894 kms / 555 miles
Airline
- Kalitta Air
- IATA: K4
- ICAO: CKS
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Boeing 747-4B5F
- Callsign: CKS9873
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in New York: Thursday 2025-11-20 00:30 AM
- Current Time in Oscoda: Thursday 2025-11-20 00:30 AM
Domestic flight Kalitta Air K49873 takes off from New York (JFK) United States to Oscoda (OSC) United States. It's operated by Kalitta Air. The plane leaves John F. Kennedy International Airport at 04:29 America/New_York. The flight is expected to land at Wurtsmith Air Force Base at None America/New_York. The flight will last about 1 hours 28 minutes.
Frequently asked questions, answered
How long is the flight from New York to Oscoda?
On average, nonstop flight takes 1 hour(s) 28 minutes, with the flight distance of 894 km (555 miles).
What type of aircraft is used for the Kalitta Air K49873 flight?
All Kalitta Air K49873 flights are operated using Boeing 747-4B5F aircraft.
