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Kalitta Air K49707 flight status now
K49707 - CKS9707
Kalitta Air (K4)
JFK
New York United States
SSC
Sumter United States
Contact Airlines
It may not operate on the date requested
K49707 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 2 minutes
- Flight Distance: 947 kms / 589 miles
Airline
- Kalitta Air
- IATA: K4
- ICAO: CKS
- Operating Days: Tuesday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Boeing 747-4B5(BCF)
- Callsign: T-F5M
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in New York: Tuesday 2025-11-18 16:10 PM
- Current Time in Sumter: Tuesday 2025-11-18 16:10 PM
Domestic flight Kalitta Air K49707 takes off from New York (JFK) United States to Sumter (SSC) United States. It's operated by Kalitta Air. The plane leaves John F. Kennedy International Airport at 11:01 America/New_York. The flight is expected to land at Shaw Air Force Base at 12:30 America/New_York. The flight will last about 1 hours 2 minutes.
Frequently asked questions, answered
How long is the flight from New York to Sumter?
On average, nonstop flight takes 1 hour(s) 2 minutes, with the flight distance of 947 km (589 miles).
What type of aircraft is used for the Kalitta Air K49707 flight?
All Kalitta Air K49707 flights are operated using Boeing 747-4B5(BCF) aircraft.
How many Kalitta Air K49707 flights are operated a week?
1 flights per week. The Flight Kalitta Air K49707 is operated on Tuesday.
