Kalitta Air K49706 flight status now

Current status of K49706 is Unknown

K49706 - CKS9706 Kalitta Air (K4)
OSC Oscoda United States
Flight OSC to JFK
JFK New York United States
Unknown
Departure Wurtsmith Air Force Base
IATA: OSCICAO: KOSC
Scheduled 11:30 18 November 2025
Estimated 11:30 18 November 2025
- -
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 12:10 18 November 2025
Estimated 12:02 18 November 2025
- -
K49706 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 4 minutes
  • Flight Distance: 894 kms / 555 miles
Airline
  • Kalitta Air
  • IATA: K4
  • ICAO: CKS
  • Operating Days: Sunday
Passenger Services
  • Service type: N/A
  • Seats: N/A
  • Freight capacity: N/A
  • Passenger classes: N/A
More Detail
  • Aircraft: Boeing 747-4B5F
  • Callsign: F-KSMO2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Oscoda: Tuesday 2025-11-18 10:05 AM
  • Current Time in New York: Tuesday 2025-11-18 10:05 AM

Domestic flight Kalitta Air K49706 takes off from Oscoda (OSC) United States to New York (JFK) United States. It's operated by Kalitta Air. The plane leaves Wurtsmith Air Force Base at 11:30 18 November 2025 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 12:10 18 November 2025 America/New_York. The flight will last about 2 hours 4 minutes.

Frequently asked questions, answered

How long is the flight from Oscoda to New York?

On average, nonstop flight takes 2 hour(s) 4 minutes, with the flight distance of 894 km (555 miles).

What type of aircraft is used for the Kalitta Air K49706 flight?

All Kalitta Air K49706 flights are operated using Boeing 747-4B5F aircraft.

Which terminal the flight Kalitta Air K49706 is arriving at?

Flight Kalitta Air K49706 arrives in John F. Kennedy International Airport at Terminal -.

How many Kalitta Air K49706 flights are operated a week?

1 flights per week. The Flight Kalitta Air K49706 is operated on Sunday.