Kalitta Air K49705 flight status now

K49705 - CKS9705 Kalitta Air (K4)
JFK New York United States
Flight JFK to OSC
OSC Oscoda United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 14:30
None None
Arrival Wurtsmith Air Force Base
IATA: OSCICAO: KOSC
Scheduled 15:52
None None
K49705 Detail
  • Type: Domestic Flight
  • Flight Duration: 49 minutes
  • Flight Distance: 894 kms / 555 miles
Airline
  • Kalitta Air
  • IATA: K4
  • ICAO: CKS
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 747-4B5F
  • Callsign: F-KFNT1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Wednesday 2025-11-19 00:23 AM
  • Current Time in Oscoda: Wednesday 2025-11-19 00:23 AM

Domestic flight Kalitta Air K49705 takes off from New York (JFK) United States to Oscoda (OSC) United States. It's operated by Kalitta Air. The plane leaves John F. Kennedy International Airport at 14:30 America/New_York. The flight is expected to land at Wurtsmith Air Force Base at 15:52 America/New_York. The flight will last about 49 minutes.

Similar flight route from New York (JFK) to Oscoda (OSC)

Airline Flight no Departure Arrival
Kalitta Air K49716
Kalitta Air 		19/11/2025
13:15 		1 hours 2 minutes
14:37

Frequently asked questions, answered

How long is the flight from New York to Oscoda?

On average, nonstop flight takes 49 minutes, with the flight distance of 894 km (555 miles).

What type of aircraft is used for the Kalitta Air K49705 flight?

All Kalitta Air K49705 flights are operated using Boeing 747-4B5F aircraft.

How many Kalitta Air K49705 flights are operated a week?

1 flights per week. The Flight Kalitta Air K49705 is operated on Friday.