Kalitta Air K4503 Flight Status Today

International flight Kalitta Air K4503 takes off from New York (JFK) United States to Rzeszow (RZE) Poland. It's operated by Kalitta Air. The plane leaves John F. Kennedy International Airport at 22:25 America/New_York. The flight is expected to land at Rzeszow International Airport at 12:04 Europe/Warsaw. The flight will last about 4 hours 35 minutes.

K4503 - CKS503 Kalitta Air (K4)
JFK New York United States
Flight JFK to RZE
RZE Rzeszow Poland
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 15-January-2020
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 22:25
None None
Arrival Rzeszow International Airport
IATA: RZEICAO: EPRZ
Scheduled 12:04
None None
K4503 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 35 minutes
  • Flight Distance: 7050 kms / 4380 miles
Airline
  • Kalitta Air
  • IATA: K4
  • ICAO: CKS
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 747-481F
  • Callsign: F-EGNC4
  • Departure Timezone: America/New_York
  • Arrival Timezone: Europe/Warsaw
  • Current Time in New York: Tuesday 2026-01-20 02:05 AM
  • Current Time in Rzeszow: Tuesday 2026-01-20 08:05 AM

Flight routes similar to Kalitta Air K4503

Airline Flight no Departure Arrival
Polish Airlines LOT LO1007
Polish Airlines LOT 		20/01/2026
03:00 		8 hours 1 minutes
17:45

Kalitta Air Flight K4503 FAQs

What is the scheduled flight duration for Kalitta Air K4503 flight?

On average, nonstop flight takes 4 hour(s) 35 minutes, with the flight distance of 7050 km (4380 miles).

What type of aircraft is used for the Kalitta Air K4503 flight?

All Kalitta Air K4503 flights are operated using Boeing 747-481F aircraft.