Jambojet JX2502 Flight Status Today

Domestic flight Jambojet JX2502 takes off from Kaohsiung (KHH) Taiwan to Taipei (TPE) Taiwan. It's operated by Jambojet. The plane leaves Kaohsiung International Airport at 09:23 Asia/Taipei. The flight is expected to land at Taiwan Taoyuan International Airport at None Asia/Taipei. The flight will last about 38 minutes.

JX2502 - JX2502 Jambojet (JX)
KHH Kaohsiung Taiwan
Flight KHH to TPE
TPE Taipei Taiwan
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Kaohsiung International Airport
IATA: KHHICAO: RCKH
Scheduled 09:23
None None
Arrival Taiwan Taoyuan International Airport
IATA: TPEICAO: RCTP
Scheduled None
None None
JX2502 Detail
  • Type: Domestic Flight
  • Flight Duration: 38 minutes
  • Flight Distance: 292 kms / 181 miles
Airline
  • Jambojet
  • IATA: JX
  • ICAO: JX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A350-941
  • Callsign: SJX2502
  • Departure Timezone: Asia/Taipei
  • Arrival Timezone: Asia/Taipei
  • Current Time in Kaohsiung: Wednesday 2026-01-21 07:19 AM
  • Current Time in Taipei: Wednesday 2026-01-21 07:19 AM

Flight routes similar to Jambojet JX2502

Airline Flight no Departure Arrival
China Airlines CI7842
China Airlines 		21/01/2026
15:55 		1 hours 12 minutes
17:07

Jambojet Flight JX2502 FAQs

What is the scheduled flight duration for Jambojet JX2502 flight?

On average, nonstop flight takes 38 minutes, with the flight distance of 292 km (181 miles).

What type of aircraft is used for the Jambojet JX2502 flight?

All Jambojet JX2502 flights are operated using Airbus A350-941 aircraft.