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Air Serbia JU8580 Flight Status Today
Domestic flight Air Serbia JU8580 takes off from West Palm Beach (PBI) United States to New York (JFK) United States. It's operated by Air Serbia. The plane leaves Palm Beach International Airport at 14:00 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 16:48 America/New_York. The flight will last about 2 hours 48 minutes.
- Type: Domestic Flight
- Flight Duration: 2 hours 48 minutes
- Flight Distance: 1654 kms / 1028 miles
- Air Serbia
- IATA: JU
- ICAO: ASL
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday
- Service type: Normal passenger
- Seats: 299
- Freight capacity: 40.2 tons
- Passenger classes: Economy, Business Class, Premium Economy
- Aircraft: Airbus A320
- Callsign: ASL8580
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in West Palm Beach: Tuesday 2026-02-10 20:30 PM
- Current Time in New York: Tuesday 2026-02-10 20:30 PM
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Air Serbia Flight JU8580 FAQs
What is the scheduled flight duration for Air Serbia JU8580 flight?
On average, nonstop flight takes 2 hour(s) 48 minutes, with the flight distance of 1654 km (1028 miles).
What type of aircraft is used for the Air Serbia JU8580 flight?
All Air Serbia JU8580 flights are operated using Airbus A320 aircraft.
Which terminal the flight Air Serbia JU8580 is arriving at?
Flight Air Serbia JU8580 arrives in John F. Kennedy International Airport at Terminal 5.
How many Air Serbia JU8580 flights are operated a week?
6 flights per week. The Flight Air Serbia JU8580 is operated on Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday.
