Air Serbia JU8578 Flight Status Today

Domestic flight Air Serbia JU8578 takes off from Kansas City (MCI) United States to New York (JFK) United States. It's operated by Air Serbia. The plane leaves Kansas City International Airport at 09:37 America/Chicago. The flight is expected to land at John F. Kennedy International Airport at 13:30 America/New_York. The flight will last about 2 hours 55 minutes.

JU8578 - ASL8578 Air Serbia (JU)
MCI Kansas City United States
Flight MCI to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-March-2019
Departure Kansas City International Airport
IATA: MCIICAO: KMCI
Scheduled 09:37
None A12
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 13:30
5 10
JU8578 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 55 minutes
  • Flight Distance: 1790 kms / 1112 miles
Airline
  • Air Serbia
  • IATA: JU
  • ICAO: ASL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 299
  • Freight capacity: 40.2 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Airbus A220-300 Passenger
  • Callsign: ASL8578
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Kansas City: Wednesday 2026-01-21 23:39 PM
  • Current Time in New York: Thursday 2026-01-22 00:39 AM

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Air France AF8830
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Kenya Airways KQ7096
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Korean Air KE7459
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Icelandair FI7898
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Air Serbia Flight JU8578 FAQs

What is the scheduled flight duration for Air Serbia JU8578 flight?

On average, nonstop flight takes 2 hour(s) 55 minutes, with the flight distance of 1790 km (1112 miles).

What type of aircraft is used for the Air Serbia JU8578 flight?

All Air Serbia JU8578 flights are operated using Airbus A220-300 Passenger aircraft.

Which terminal the flight Air Serbia JU8578 is arriving at?

Flight Air Serbia JU8578 arrives in John F. Kennedy International Airport at Terminal 5.