Air Serbia JU8568 Flight Status Today

Domestic flight Air Serbia JU8568 takes off from New York (JFK) United States to Fort Myers (RSW) United States. It's operated by Air Serbia. The plane leaves John F. Kennedy International Airport at 14:35 America/New_York. The flight is expected to land at Southwest Florida International Airport at 17:56 America/New_York. The flight will last about 3 hours 21 minutes.

JU8568 - ASL8568 Air Serbia (JU)
JFK New York United States
Flight JFK to RSW
RSW Fort Myers United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 14:35
5 526
Arrival Southwest Florida International Airport
IATA: RSWICAO: KRSW
Scheduled 17:56
None D8
JU8568 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 21 minutes
  • Flight Distance: 1730 kms / 1075 miles
Airline
  • Air Serbia
  • IATA: JU
  • ICAO: ASL
  • Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 136
  • Freight capacity: 0.5 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: ASL8568
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Monday 2026-02-09 16:04 PM
  • Current Time in Fort Myers: Monday 2026-02-09 16:04 PM

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Air Serbia Flight JU8568 FAQs

What is the scheduled flight duration for Air Serbia JU8568 flight?

On average, nonstop flight takes 3 hour(s) 21 minutes, with the flight distance of 1730 km (1075 miles).

What type of aircraft is used for the Air Serbia JU8568 flight?

All Air Serbia JU8568 flights are operated using Airbus A320 (sharklets) aircraft.

How many Air Serbia JU8568 flights are operated a week?

6 flights per week. The Flight Air Serbia JU8568 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.