Air Serbia JU8568 Flight Status Today

Domestic flight Air Serbia JU8568 takes off from New York (JFK) United States to Fort Myers (RSW) United States. It's operated by Air Serbia. The plane leaves John F. Kennedy International Airport at 20:29 America/New_York. The flight is expected to land at Southwest Florida International Airport at 23:52 America/New_York. The flight will last about 3 hours 23 minutes.

JU8568 - ASL8568 Air Serbia (JU)
JFK New York United States
Flight JFK to RSW
RSW Fort Myers United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:29
5 505
Arrival Southwest Florida International Airport
IATA: RSWICAO: KRSW
Scheduled 23:52
None D8
JU8568 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 23 minutes
  • Flight Distance: 1730 kms / 1075 miles
Airline
  • Air Serbia
  • IATA: JU
  • ICAO: ASL
  • Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 136
  • Freight capacity: 0.5 tons
  • Passenger classes: Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Airbus A220-300 Passenger
  • Callsign: ASL8568
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Sunday 2026-03-22 22:12 PM
  • Current Time in Fort Myers: Sunday 2026-03-22 22:12 PM

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Air Serbia Flight JU8568 FAQs

What is the scheduled flight duration for Air Serbia JU8568 flight?

On average, nonstop flight takes 3 hour(s) 23 minutes, with the flight distance of 1730 km (1075 miles).

What type of aircraft is used for the Air Serbia JU8568 flight?

All Air Serbia JU8568 flights are operated using Airbus A220-300 Passenger aircraft.

How many Air Serbia JU8568 flights are operated a week?

6 flights per week. The Flight Air Serbia JU8568 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.