Air Serbia JU7364 Flight Status Today

Domestic flight Air Serbia JU7364 takes off from Venice (VCE) Italy to Rome (FCO) Italy. It's operated by Air Serbia. The plane leaves Venice Marco Polo Airport at 11:15 Europe/Rome. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at 12:25 Europe/Rome. The flight will last about 1 hours 10 minutes.

JU7364 - ASL7364 Air Serbia (JU)
VCE Venice Italy
Flight VCE to FCO
FCO Rome Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 09-April-2020
Departure Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 11:15
None None
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 12:25
1 None
JU7364 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 412 kms / 256 miles
Airline
  • Air Serbia
  • IATA: JU
  • ICAO: ASL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 180
  • Freight capacity: 9.4 tons
  • Passenger classes: Economy, Shuttle
More Detail
  • Aircraft: Airbus A319
  • Callsign: ASL7364
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Venice: Saturday 2026-02-28 20:15 PM
  • Current Time in Rome: Saturday 2026-02-28 20:15 PM

Flight routes similar to Air Serbia JU7364

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Aerolineas Argentinas AR7241
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United Airlines UA7769
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China Airlines CI9252
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Air Serbia Flight JU7364 FAQs

What is the scheduled flight duration for Air Serbia JU7364 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 412 km (256 miles).

What type of aircraft is used for the Air Serbia JU7364 flight?

All Air Serbia JU7364 flights are operated using Airbus A319 aircraft.

Which terminal the flight Air Serbia JU7364 is arriving at?

Flight Air Serbia JU7364 arrives in Leonardo da Vinci-Fiumicino Airport at Terminal 1.