Jetstar JQ748 Flight Status Today

Domestic flight Jetstar JQ748 takes off from Launceston (LST) Australia to Sydney (SYD) Australia. It's operated by Jetstar Airways. The plane leaves Launceston Airport at 08:30 Australia/Hobart. The flight is expected to land at Sydney Airport at 10:10 Australia/Sydney. The flight will last about 1 hours 53 minutes.

JQ748 - JST748 Jetstar Airways (JQ)
LST Launceston Australia
Flight LST to SYD
SYD Sydney Australia
Contact Airlines It may not operate on the date requested
Departure Launceston Airport
IATA: LSTICAO: YMLT
Scheduled 08:30
None 1-2
Arrival Sydney Airport
IATA: SYDICAO: YSSY
Scheduled 10:10
2 A35
JQ748 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 53 minutes
  • Flight Distance: 914 kms / 568 miles
Airline
  • Jetstar Airways
  • IATA: JQ
  • ICAO: JST
  • Operating Days: Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 180
  • Freight capacity: 9.4 tons
  • Passenger classes: First Class, Economy
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-YSSY4
  • Departure Timezone: Australia/Hobart
  • Arrival Timezone: Australia/Sydney
  • Current Time in Launceston: Saturday 2026-04-11 15:20 PM
  • Current Time in Sydney: Saturday 2026-04-11 15:20 PM

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Jetstar Flight JQ748 FAQs

What is the scheduled flight duration for Jetstar JQ748 flight?

On average, nonstop flight takes 1 hour(s) 53 minutes, with the flight distance of 914 km (568 miles).

What type of aircraft is used for the Jetstar JQ748 flight?

All Jetstar JQ748 flights are operated using Airbus A320 aircraft.

Which terminal the flight Jetstar JQ748 is arriving at?

Flight Jetstar JQ748 arrives in Sydney Airport at Terminal 2.

How many Jetstar JQ748 flights are operated a week?

1 flights per week. The Flight Jetstar JQ748 is operated on Sunday.