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Jazeera Airways J9707 Flight Status Today
International flight Jazeera Airways J9707 takes off from Kuwait (KWI) Kuwait to Luxor (LXR) Egypt. It's operated by Jazeera Airways. The plane leaves Kuwait International Airport at 01:35 18 January 2026 Asia/Kuwait. The flight is expected to land at Luxor International Airport at 03:20 18 January 2026 Africa/Cairo. The flight will last about 2 hours 45 minutes.
Current status of J9707 is Scheduled On time Expected Depart in 31 minutes
J9707 - JZR707
Jazeera Airways (J9)
KWI
Kuwait Kuwait
LXR
Luxor Egypt
Scheduled On time
Expected Depart in 31 minutes
J9707 Detail
- Type: International Flight
- Flight Duration: 2 hours 45 minutes
- Flight Distance: 1559 kms / 969 miles
Airline
- Jazeera Airways
- IATA: J9
- ICAO: JZR
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Sunday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Airbus A320
- Callsign: F-OKBK6
- Departure Timezone: Asia/Kuwait
- Arrival Timezone: Africa/Cairo
- Current Time in Kuwait: Sunday 2026-01-18 01:04 AM
- Current Time in Luxor: Sunday 2026-01-18 00:04 AM
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Jazeera Airways Flight J9707 FAQs
What is the scheduled flight duration for Jazeera Airways J9707 flight?
On average, nonstop flight takes 2 hour(s) 45 minutes, with the flight distance of 1559 km (969 miles).
What is the current status of Jazeera Airways J9707 flight?
The current status of flight Jazeera Airways J9707 is Scheduled On time.
What type of aircraft is used for the Jazeera Airways J9707 flight?
All Jazeera Airways J9707 flights are operated using Airbus A320 aircraft.
How many Jazeera Airways J9707 flights are operated a week?
6 flights per week. The Flight Jazeera Airways J9707 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Sunday.