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Jazeera Airways J9608 flight status now
J9608 - JZR608
Jazeera Airways (J9)
KWI
Kuwait Kuwait
HYD
Hyderabad India
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 27-October-2018
J9608 Detail
- Type: International Flight
- Flight Duration: 5 hours 0 minutes
- Flight Distance: 3375 kms / 2097 miles
Airline
- Jazeera Airways
- IATA: J9
- ICAO: JZR
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: Asia/Kuwait
- Arrival Timezone: Asia/Kolkata
- Current Time in Kuwait: Tuesday 2025-11-18 20:16 PM
- Current Time in Hyderabad: Tuesday 2025-11-18 22:46 PM
International flight Jazeera Airways J9608 takes off from Kuwait (KWI) Kuwait to Hyderabad (HYD) India. It's operated by Jazeera Airways. The plane leaves Kuwait International Airport at 18:25 Asia/Kuwait. The flight is expected to land at Rajiv Gandhi International Airport at 01:35 Asia/Kolkata. The flight will last about 5 hours 0 minutes.
Similar flight route from Kuwait (KWI) to Hyderabad (HYD)
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
J9403 Jazeera Airways |
18/11/2025 18:55 |
4 hours 15 minutes 01:40 |
|
6E1234 IndiGo |
18/11/2025 01:15 |
4 hours 25 minutes 08:10 |
|
KU373 Kuwait Airways |
18/11/2025 19:15 |
4 hours 35 minutes 02:20 |
|
KU375 Kuwait Airways |
18/11/2025 23:55 |
4 hours 20 minutes 07:05 |
|
IX8 Air India Express |
18/11/2025 None |
4 hours 37 minutes 19:45 |
Frequently asked questions, answered
How long is the flight from Kuwait to Hyderabad?
On average, nonstop flight takes 5 hour(s) 0 minutes, with the flight distance of 3375 km (2097 miles).
