Jazeera Airways J9608 Flight Status Today

International flight Jazeera Airways J9608 takes off from Kuwait (KWI) Kuwait to Hyderabad (HYD) India. It's operated by Jazeera Airways. The plane leaves Kuwait International Airport at 18:25 Asia/Kuwait. The flight is expected to land at Rajiv Gandhi International Airport at 01:35 Asia/Kolkata. The flight will last about 5 hours 0 minutes.

J9608 - JZR608 Jazeera Airways (J9)
KWI Kuwait Kuwait
Flight KWI to HYD
HYD Hyderabad India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 27-October-2018
Departure Kuwait International Airport
IATA: KWIICAO: OKBK
Scheduled 18:25
None None
Arrival Rajiv Gandhi International Airport
IATA: HYDICAO: VOHS
Scheduled 01:35
None None
J9608 Detail
  • Type: International Flight
  • Flight Duration: 5 hours 0 minutes
  • Flight Distance: 3375 kms / 2097 miles
Airline
  • Jazeera Airways
  • IATA: J9
  • ICAO: JZR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: Asia/Kuwait
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Kuwait: Thursday 2026-01-01 06:11 AM
  • Current Time in Hyderabad: Thursday 2026-01-01 08:41 AM

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None 		4 hours 37 minutes
19:45

Jazeera Airways Flight J9608 FAQs

What is the scheduled flight duration for Jazeera Airways J9608 flight?

On average, nonstop flight takes 5 hour(s) 0 minutes, with the flight distance of 3375 km (2097 miles).