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Jazeera Airways J9512 Flight Status Today
International flight Jazeera Airways J9512 takes off from Islamabad (ISB) Pakistan to Kuwait (KWI) Kuwait. It's operated by Jazeera Airways. The plane leaves Islamabad International Airport at 05:40 01 January 2026 Asia/Karachi. The flight is expected to land at Kuwait International Airport at 08:00 01 January 2026 Asia/Kuwait. The flight will last about 4 hours 20 minutes.
Current status of J9512 is Scheduled On time Expected Depart in 4 hours, 21 minutes
- Type: International Flight
- Flight Duration: 4 hours 20 minutes
- Flight Distance: 2405 kms / 1495 miles
- Jazeera Airways
- IATA: J9
- ICAO: JZR
- Operating Days: Thursday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320neo
- Callsign: F-OKBK6
- Departure Timezone: Asia/Karachi
- Arrival Timezone: Asia/Kuwait
- Current Time in Islamabad: Thursday 2026-01-01 01:19 AM
- Current Time in Kuwait: Wednesday 2025-12-31 23:19 PM
Jazeera Airways Flight J9512 FAQs
What is the scheduled flight duration for Jazeera Airways J9512 flight?
On average, nonstop flight takes 4 hour(s) 20 minutes, with the flight distance of 2405 km (1495 miles).
What is the current status of Jazeera Airways J9512 flight?
The current status of flight Jazeera Airways J9512 is Scheduled On time.
What type of aircraft is used for the Jazeera Airways J9512 flight?
All Jazeera Airways J9512 flights are operated using Airbus A320neo aircraft.
When does the flight Jazeera Airways J9512 arrive?
Flight Jazeera Airways J9512 arrives at 08:00.
Which terminal the flight Jazeera Airways J9512 is arriving at?
Flight Jazeera Airways J9512 arrives in Kuwait International Airport at Terminal 5.
How many Jazeera Airways J9512 flights are operated a week?
2 flights per week. The Flight Jazeera Airways J9512 is operated on Thursday, Sunday.
