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Jazeera Airways J9512 Flight Status
- Type: International Flight
- Flight Duration: 4 hours 15 minutes
- Flight Distance: 2405 kms / 1495 miles
- Jazeera Airways
- IATA: J9
- ICAO: JZR
- Operating Days: Thursday, Sunday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Airbus A320
- Callsign: F-OKBK6
- Departure Timezone: Asia/Karachi
- Arrival Timezone: Asia/Kuwait
- Current Time in Islamabad: Wednesday 2025-12-10 13:18 PM
- Current Time in Kuwait: Wednesday 2025-12-10 11:18 AM
International flight Jazeera Airways J9512 takes off from Islamabad (ISB) Pakistan to Kuwait (KWI) Kuwait. It's operated by Jazeera Airways. The plane leaves Islamabad International Airport at 05:40 Asia/Karachi. The flight is expected to land at Kuwait International Airport at 07:55 Asia/Kuwait. The flight will last about 4 hours 15 minutes.
Frequently asked questions, answered
What is the scheduled flight duration for Jazeera Airways J9512 flight?
On average, nonstop flight takes 4 hour(s) 15 minutes, with the flight distance of 2405 km (1495 miles).
What type of aircraft is used for the Jazeera Airways J9512 flight?
All Jazeera Airways J9512 flights are operated using Airbus A320 aircraft.
Which terminal the flight Jazeera Airways J9512 is arriving at?
Flight Jazeera Airways J9512 arrives in Kuwait International Airport at Terminal 5.
How many Jazeera Airways J9512 flights are operated a week?
2 flights per week. The Flight Jazeera Airways J9512 is operated on Thursday, Sunday.
