Jazeera Airways J9507 Flight Status Today

International flight Jazeera Airways J9507 takes off from Kuwait (KWI) Kuwait to Karachi (KHI) Pakistan. It's operated by Jazeera Airways. The plane leaves Kuwait International Airport at 21:45 29 December 2025 Asia/Kuwait. The flight is expected to land at Jinnah International Airport at 02:30 30 December 2025 Asia/Karachi. The flight will last about 2 hours 45 minutes.

Current status of J9507 is Scheduled On time Expected Depart in 8 hours, 53 minutes

J9507 - JZR507 Jazeera Airways (J9)
KWI Kuwait Kuwait
Flight KWI to KHI
KHI Karachi Pakistan
Scheduled On time Expected Depart in 8 hours, 53 minutes
Departure Kuwait International Airport
IATA: KWIICAO: OKBK
Scheduled 21:45 29 December 2025
5 None
Arrival Jinnah International Airport
IATA: KHIICAO: OPKC
Scheduled 02:30 30 December 2025
None None
J9507 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 45 minutes
  • Flight Distance: 1961 kms / 1219 miles
Airline
  • Jazeera Airways
  • IATA: J9
  • ICAO: JZR
  • Operating Days: Monday
Passenger Services
  • Service type: N/A
  • Seats: N/A
  • Freight capacity: N/A
  • Passenger classes: N/A
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-OISS2
  • Departure Timezone: Asia/Kuwait
  • Arrival Timezone: Asia/Karachi
  • Current Time in Kuwait: Monday 2025-12-29 12:52 PM
  • Current Time in Karachi: Monday 2025-12-29 14:52 PM

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Jazeera Airways Flight J9507 FAQs

What is the scheduled flight duration for Jazeera Airways J9507 flight?

On average, nonstop flight takes 2 hour(s) 45 minutes, with the flight distance of 1961 km (1219 miles).

What is the current status of Jazeera Airways J9507 flight?

The current status of flight Jazeera Airways J9507 is Scheduled On time.

What type of aircraft is used for the Jazeera Airways J9507 flight?

All Jazeera Airways J9507 flights are operated using Airbus A320 aircraft.

How many Jazeera Airways J9507 flights are operated a week?

1 flights per week. The Flight Jazeera Airways J9507 is operated on Monday.