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Jazeera Airways J9408 Flight Status Today
International flight Jazeera Airways J9408 takes off from Ahmedabad (AMD) India to Kuwait (KWI) Kuwait. It's operated by Jazeera Airways. The plane leaves Ahmedabad Airport at 06:30 Asia/Kolkata. The flight is expected to land at Kuwait International Airport at 08:25 Asia/Kuwait. The flight will last about 4 hours 25 minutes.
J9408 - JZR408
Jazeera Airways (J9)
AMD
Ahmedabad India
KWI
Kuwait Kuwait
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It may not operate on the date requested
J9408 Detail
- Type: International Flight
- Flight Duration: 4 hours 25 minutes
- Flight Distance: 2553 kms / 1586 miles
Airline
- Jazeera Airways
- IATA: J9
- ICAO: JZR
- Operating Days: Saturday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Airbus A320neo
- Callsign: F-OKBK6
- Departure Timezone: Asia/Kolkata
- Arrival Timezone: Asia/Kuwait
- Current Time in Ahmedabad: Sunday 2026-02-08 21:21 PM
- Current Time in Kuwait: Sunday 2026-02-08 18:51 PM
Flight routes similar to Jazeera Airways J9408
Jazeera Airways Flight J9408 FAQs
What is the scheduled flight duration for Jazeera Airways J9408 flight?
On average, nonstop flight takes 4 hour(s) 25 minutes, with the flight distance of 2553 km (1586 miles).
What type of aircraft is used for the Jazeera Airways J9408 flight?
All Jazeera Airways J9408 flights are operated using Airbus A320neo aircraft.
Which terminal the flight Jazeera Airways J9408 is arriving at?
Flight Jazeera Airways J9408 arrives in Kuwait International Airport at Terminal 5.
How many Jazeera Airways J9408 flights are operated a week?
1 flights per week. The Flight Jazeera Airways J9408 is operated on Saturday.