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Jazeera Airways J9403 Flight Status Today
International flight Jazeera Airways J9403 takes off from Kuwait (KWI) Kuwait to Hyderabad (HYD) India. It's operated by Jazeera Airways. The plane leaves Kuwait International Airport at 18:50 21 January 2026 Asia/Kuwait. The flight is expected to land at Rajiv Gandhi International Airport at 01:40 22 January 2026 Asia/Kolkata. The flight will last about 4 hours 20 minutes.
Current status of J9403 is Departed On time Estimated Arrival in 47 minutes
- Type: International Flight
- Flight Duration: 4 hours 20 minutes
- Flight Distance: 3375 kms / 2097 miles
- Jazeera Airways
- IATA: J9
- ICAO: JZR
- Operating Days: Tuesday, Wednesday, Saturday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320neo
- Callsign: F-VOHS2
- Departure Timezone: Asia/Kuwait
- Arrival Timezone: Asia/Kolkata
- Current Time in Kuwait: Wednesday 2026-01-21 22:28 PM
- Current Time in Hyderabad: Thursday 2026-01-22 00:58 AM
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Jazeera Airways Flight J9403 FAQs
What is the scheduled flight duration for Jazeera Airways J9403 flight?
On average, nonstop flight takes 4 hour(s) 20 minutes, with the flight distance of 3375 km (2097 miles).
What is the current status of Jazeera Airways J9403 flight?
The current status of flight Jazeera Airways J9403 is Departed On time.
What type of aircraft is used for the Jazeera Airways J9403 flight?
All Jazeera Airways J9403 flights are operated using Airbus A320neo aircraft.
How many Jazeera Airways J9403 flights are operated a week?
3 flights per week. The Flight Jazeera Airways J9403 is operated on Tuesday, Wednesday, Saturday.
