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Jazeera Airways J9403 flight status now
Current status of J9403 is Scheduled On time Expected Depart in 5 hours, 29 minutes
- Type: International Flight
- Flight Duration: 4 hours 15 minutes
- Flight Distance: 3375 kms / 2097 miles
- Jazeera Airways
- IATA: J9
- ICAO: JZR
- Operating Days: Tuesday, Wednesday, Saturday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320
- Callsign: F-VOHS2
- Departure Timezone: Asia/Kuwait
- Arrival Timezone: Asia/Kolkata
- Current Time in Kuwait: Tuesday 2025-11-18 13:26 PM
- Current Time in Hyderabad: Tuesday 2025-11-18 15:56 PM
International flight Jazeera Airways J9403 takes off from Kuwait (KWI) Kuwait to Hyderabad (HYD) India. It's operated by Jazeera Airways. The plane leaves Kuwait International Airport at 18:55 18 November 2025 Asia/Kuwait. The flight is expected to land at Rajiv Gandhi International Airport at 01:40 19 November 2025 Asia/Kolkata. The flight will last about 4 hours 15 minutes.
Similar flight route from Kuwait (KWI) to Hyderabad (HYD)
Frequently asked questions, answered
How long is the flight from Kuwait to Hyderabad?
On average, nonstop flight takes 4 hour(s) 15 minutes, with the flight distance of 3375 km (2097 miles).
What type of aircraft is used for the Jazeera Airways J9403 flight?
All Jazeera Airways J9403 flights are operated using Airbus A320 aircraft.
How many Jazeera Airways J9403 flights are operated a week?
3 flights per week. The Flight Jazeera Airways J9403 is operated on Tuesday, Wednesday, Saturday.
