Jazeera Airways J91708 Flight Status Today

International flight Jazeera Airways J91708 takes off from Luxor (LXR) Egypt to Kuwait (KWI) Kuwait. It's operated by Jazeera Airways. The plane leaves Luxor International Airport at 07:05 Africa/Cairo. The flight is expected to land at Kuwait International Airport at 10:25 Asia/Kuwait. The flight will last about 2 hours 20 minutes.

J91708 - JZR1708 Jazeera Airways (J9)
LXR Luxor Egypt
Flight LXR to KWI
KWI Kuwait Kuwait
Contact Airlines It may not operate on the date requested
Departure Luxor International Airport
IATA: LXRICAO: HELX
Scheduled 07:05
None None
Arrival Kuwait International Airport
IATA: KWIICAO: OKBK
Scheduled 10:25
5 None
J91708 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 20 minutes
  • Flight Distance: 1559 kms / 969 miles
Airline
  • Jazeera Airways
  • IATA: J9
  • ICAO: JZR
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-OKBK6
  • Departure Timezone: Africa/Cairo
  • Arrival Timezone: Asia/Kuwait
  • Current Time in Luxor: Monday 2026-01-19 16:46 PM
  • Current Time in Kuwait: Monday 2026-01-19 17:46 PM

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Jazeera Airways Flight J91708 FAQs

What is the scheduled flight duration for Jazeera Airways J91708 flight?

On average, nonstop flight takes 2 hour(s) 20 minutes, with the flight distance of 1559 km (969 miles).

What type of aircraft is used for the Jazeera Airways J91708 flight?

All Jazeera Airways J91708 flights are operated using Airbus A320 aircraft.

Which terminal the flight Jazeera Airways J91708 is arriving at?

Flight Jazeera Airways J91708 arrives in Kuwait International Airport at Terminal 5.

How many Jazeera Airways J91708 flights are operated a week?

1 flights per week. The Flight Jazeera Airways J91708 is operated on Monday.