Jazeera Airways J91448 flight status now

J91448 - JZR1448 Jazeera Airways (J9)
LKO Lucknow India
Flight LKO to KWI
KWI Kuwait Kuwait
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled 01:47
None None
Arrival Kuwait International Airport
IATA: KWIICAO: OKBK
Scheduled None
None None
J91448 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 9 minutes
  • Flight Distance: 3238 kms / 2012 miles
Airline
  • Jazeera Airways
  • IATA: J9
  • ICAO: JZR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320-251N
  • Callsign: JZR1448
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kuwait
  • Current Time in Lucknow: Saturday 2025-11-22 02:35 AM
  • Current Time in Kuwait: Saturday 2025-11-22 00:05 AM

International flight Jazeera Airways J91448 takes off from Lucknow (LKO) India to Kuwait (KWI) Kuwait. It's operated by Jazeera Airways. The plane leaves Chaudhary Charan Singh International Airport at 01:47 Asia/Kolkata. The flight is expected to land at Kuwait International Airport at None Asia/Kuwait. The flight will last about 4 hours 9 minutes.

Frequently asked questions, answered

How long is the flight from Lucknow to Kuwait?

On average, nonstop flight takes 4 hour(s) 9 minutes, with the flight distance of 3238 km (2012 miles).

What type of aircraft is used for the Jazeera Airways J91448 flight?

All Jazeera Airways J91448 flights are operated using Airbus A320-251N aircraft.