Jazeera Airways J91447 Flight Status Today

International flight Jazeera Airways J91447 takes off from Kuwait (KWI) Kuwait to Lucknow (LKO) India. It's operated by Jazeera Airways. The plane leaves Kuwait International Airport at 22:57 Asia/Kuwait. The flight is expected to land at Chaudhary Charan Singh International Airport at None Asia/Kolkata. The flight will last about 4 hours 4 minutes.

J91447 - JZR1447 Jazeera Airways (J9)
KWI Kuwait Kuwait
Flight KWI to LKO
LKO Lucknow India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Kuwait International Airport
IATA: KWIICAO: OKBK
Scheduled 22:57
None None
Arrival Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled None
None None
J91447 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 4 minutes
  • Flight Distance: 3238 kms / 2012 miles
Airline
  • Jazeera Airways
  • IATA: J9
  • ICAO: JZR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320-251N
  • Callsign: JZR1447
  • Departure Timezone: Asia/Kuwait
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Kuwait: Saturday 2026-01-24 06:22 AM
  • Current Time in Lucknow: Saturday 2026-01-24 08:52 AM

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Jazeera Airways Flight J91447 FAQs

What is the scheduled flight duration for Jazeera Airways J91447 flight?

On average, nonstop flight takes 4 hour(s) 4 minutes, with the flight distance of 3238 km (2012 miles).

What type of aircraft is used for the Jazeera Airways J91447 flight?

All Jazeera Airways J91447 flights are operated using Airbus A320-251N aircraft.