Check your Flight status online
Air India Express IX712 Flight Status Today
International flight Air India Express IX712 takes off from Muscat (MCT) Oman to Kannur (CNN) India. It's operated by Air India Express. The plane leaves Muscat International Airport at 22:00 18 January 2026 Asia/Muscat. The flight is expected to land at Kannur International Airport at 03:00 19 January 2026 Asia/Kolkata. The flight will last about 3 hours 30 minutes.
Current status of IX712 is Scheduled On time Expected Depart in 9 hours, 50 minutes
IX712 - AXB712
Air India Express (IX)
MCT
Muscat Oman
CNN
Kannur India
Scheduled On time
Expected Depart in 9 hours, 50 minutes
Scheduled
22:00 18 January 2026
None
None
IX712 Detail
- Type: International Flight
- Code Shares: AI 9146
- Flight Duration: 3 hours 30 minutes
- Flight Distance: 2237 kms / 1390 miles
Airline
- Air India Express
- IATA: IX
- ICAO: AXB
- Operating Days: Thursday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
- Callsign: F-OOMS6
- Departure Timezone: Asia/Muscat
- Arrival Timezone: Asia/Kolkata
- Current Time in Muscat: Sunday 2026-01-18 12:10 PM
- Current Time in Kannur: Sunday 2026-01-18 13:40 PM
Air India Express Flight IX712 FAQs
What is the scheduled flight duration for Air India Express IX712 flight?
On average, nonstop flight takes 3 hour(s) 30 minutes, with the flight distance of 2237 km (1390 miles).
What is the current status of Air India Express IX712 flight?
The current status of flight Air India Express IX712 is Scheduled On time.
What type of aircraft is used for the Air India Express IX712 flight?
All Air India Express IX712 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.
How many Air India Express IX712 flights are operated a week?
1 flights per week. The Flight Air India Express IX712 is operated on Thursday.