Air India Express IX6605 Flight Status Today

Domestic flight Air India Express IX6605 takes off from Mumbai (BOM) India to Lucknow (LKO) India. It's operated by Air India Express. The plane leaves Chhatrapati Shivaji International Airport at 11:15 Asia/Kolkata. The flight is expected to land at Chaudhary Charan Singh International Airport at 13:35 Asia/Kolkata. The flight will last about 2 hours 20 minutes.

IX6605 - AXB6605 Air India Express (IX)
BOM Mumbai India
Flight BOM to LKO
LKO Lucknow India
Contact Airlines It may not operate on the date requested
Departure Chhatrapati Shivaji International Airport
IATA: BOMICAO: VABB
Scheduled 11:15
None None
Arrival Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled 13:35
None None
IX6605 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 20 minutes
  • Flight Distance: 1182 kms / 734 miles
Airline
  • Air India Express
  • IATA: IX
  • ICAO: AXB
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: AXB6605
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Mumbai: Monday 2026-05-04 01:46 AM
  • Current Time in Lucknow: Monday 2026-05-04 01:46 AM

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Air India Express Flight IX6605 FAQs

What is the scheduled flight duration for Air India Express IX6605 flight?

On average, nonstop flight takes 2 hour(s) 20 minutes, with the flight distance of 1182 km (734 miles).

What type of aircraft is used for the Air India Express IX6605 flight?

All Air India Express IX6605 flights are operated using Boeing 737MAX 8 Passenger aircraft.