Air India Express IX2806 Flight Status Today

Domestic flight Air India Express IX2806 takes off from Bhubaneswar (BBI) India to Lucknow (LKO) India. It's operated by Air India Express. The plane leaves Biju Patnaik International Airport at 17:15 Asia/Kolkata. The flight is expected to land at Chaudhary Charan Singh International Airport at 19:00 Asia/Kolkata. The flight will last about 1 hours 45 minutes.

IX2806 - AXB2806 Air India Express (IX)
BBI Bhubaneswar India
Flight BBI to LKO
LKO Lucknow India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-March-2025
Departure Biju Patnaik International Airport
IATA: BBIICAO: VEBS
Scheduled 17:15
None None
Arrival Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled 19:00
None None
IX2806 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 45 minutes
  • Flight Distance: 879 kms / 546 miles
Airline
  • Air India Express
  • IATA: IX
  • ICAO: AXB
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: AXB2806
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Bhubaneswar: Friday 2026-01-23 00:25 AM
  • Current Time in Lucknow: Friday 2026-01-23 00:25 AM

Flight routes similar to Air India Express IX2806

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Air India Express Flight IX2806 FAQs

What is the scheduled flight duration for Air India Express IX2806 flight?

On average, nonstop flight takes 1 hour(s) 45 minutes, with the flight distance of 879 km (546 miles).

What type of aircraft is used for the Air India Express IX2806 flight?

All Air India Express IX2806 flights are operated using Airbus A320 (sharklets) aircraft.