Air India Express IX2428 Flight Status Today

Domestic flight Air India Express IX2428 takes off from Lucknow (LKO) India to Bengaluru (BLR) India. It's operated by Air India Express. The plane leaves Chaudhary Charan Singh International Airport at 08:50 Asia/Kolkata. The flight is expected to land at Kempegowda International Airport at 11:25 Asia/Kolkata. The flight will last about 2 hours 50 minutes.

IX2428 - AXB2428 Air India Express (IX)
LKO Lucknow India
Flight LKO to BLR
BLR Bengaluru India
Contact Airlines It may not operate on the date requested
Departure Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled 08:50
None None
Arrival Kempegowda International Airport
IATA: BLRICAO: VOBL
Scheduled 11:25
2 D6
IX2428 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 50 minutes
  • Flight Distance: 1538 kms / 955 miles
Airline
  • Air India Express
  • IATA: IX
  • ICAO: AXB
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Lucknow: Tuesday 2026-02-10 02:49 AM
  • Current Time in Bengaluru: Tuesday 2026-02-10 02:49 AM

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Air India Express Flight IX2428 FAQs

What is the scheduled flight duration for Air India Express IX2428 flight?

On average, nonstop flight takes 2 hour(s) 50 minutes, with the flight distance of 1538 km (955 miles).

What type of aircraft is used for the Air India Express IX2428 flight?

All Air India Express IX2428 flights are operated using Airbus A320 aircraft.

Which terminal the flight Air India Express IX2428 is arriving at?

Flight Air India Express IX2428 arrives in Kempegowda International Airport at Terminal 2.

How many Air India Express IX2428 flights are operated a week?

1 flights per week. The Flight Air India Express IX2428 is operated on Tuesday.