Air India Express IX1785 Flight Status Today

Domestic flight Air India Express IX1785 takes off from Lucknow (LKO) India to Mumbai (BOM) India. It's operated by Air India Express. The plane leaves Chaudhary Charan Singh International Airport at 21:40 Asia/Kolkata. The flight is expected to land at Chhatrapati Shivaji International Airport at 23:50 Asia/Kolkata. The flight will last about 2 hours 10 minutes.

IX1785 - AXB1785 Air India Express (IX)
LKO Lucknow India
Flight LKO to BOM
BOM Mumbai India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 07-September-2023
Departure Chaudhary Charan Singh International Airport
IATA: LKOICAO: VILK
Scheduled 21:40
None None
Arrival Chhatrapati Shivaji International Airport
IATA: BOMICAO: VABB
Scheduled 23:50
2 None
IX1785 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 10 minutes
  • Flight Distance: 1182 kms / 734 miles
Airline
  • Air India Express
  • IATA: IX
  • ICAO: AXB
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-VAAU1
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Lucknow: Monday 2026-01-19 05:02 AM
  • Current Time in Mumbai: Monday 2026-01-19 05:02 AM

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Air India Express Flight IX1785 FAQs

What is the scheduled flight duration for Air India Express IX1785 flight?

On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 1182 km (734 miles).

What type of aircraft is used for the Air India Express IX1785 flight?

All Air India Express IX1785 flights are operated using Boeing 737MAX 8 Passenger aircraft.

Which terminal the flight Air India Express IX1785 is arriving at?

Flight Air India Express IX1785 arrives in Chhatrapati Shivaji International Airport at Terminal 2.