Uzbekistan Airways HY7208 Flight Status Today

Domestic flight Uzbekistan Airways HY7208 takes off from Venice (VCE) Italy to Rome (FCO) Italy. It's operated by Uzbekistan Airways. The plane leaves Venice Marco Polo Airport at 07:20 Europe/Rome. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at 08:30 Europe/Rome. The flight will last about 1 hours 5 minutes.

HY7208 - UZB7208 Uzbekistan Airways (HY)
VCE Venice Italy
Flight VCE to FCO
FCO Rome Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 24-October-2019
Departure Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 07:20
T1
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 08:30
HY7208 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 5 minutes
  • Flight Distance: 412 kms / 256 miles
Airline
  • Uzbekistan Airways
  • IATA: HY
  • ICAO: UZB
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Venice: Saturday 2026-02-28 22:35 PM
  • Current Time in Rome: Saturday 2026-02-28 22:35 PM

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Uzbekistan Airways Flight HY7208 FAQs

What is the scheduled flight duration for Uzbekistan Airways HY7208 flight?

On average, nonstop flight takes 1 hour(s) 5 minutes, with the flight distance of 412 km (256 miles).