Uzbekistan Airways HY7207 Flight Status Today

Domestic flight Uzbekistan Airways HY7207 takes off from Rome (FCO) Italy to Venice (VCE) Italy. It's operated by Uzbekistan Airways. The plane leaves Leonardo da Vinci-Fiumicino Airport at 13:30 Europe/Rome. The flight is expected to land at Venice Marco Polo Airport at 14:40 Europe/Rome. The flight will last about 1 hours 1 minutes.

HY7207 - UZB7207 Uzbekistan Airways (HY)
FCO Rome Italy
Flight FCO to VCE
VCE Venice Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 22-October-2020
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 13:30
1 B30
Arrival Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 14:40
None None
HY7207 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 1 minutes
  • Flight Distance: 412 kms / 256 miles
Airline
  • Uzbekistan Airways
  • IATA: HY
  • ICAO: UZB
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Rome: Sunday 2026-02-08 03:10 AM
  • Current Time in Venice: Sunday 2026-02-08 03:10 AM

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Uzbekistan Airways Flight HY7207 FAQs

What is the scheduled flight duration for Uzbekistan Airways HY7207 flight?

On average, nonstop flight takes 1 hour(s) 1 minutes, with the flight distance of 412 km (256 miles).