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Amapola HP6338 Flight Status Today
Domestic flight Amapola HP6338 takes off from Midland (MAF) United States to Houston (IAH) United States. It's operated by Amapola. The plane leaves Midland International Airport at 18:21 America/Chicago. The flight is expected to land at George Bush Intercontinental Airport at 19:41 America/Chicago. The flight will last about 1 hours 20 minutes.
HP6338 - APF6338
Amapola (HP)
MAF
Midland United States
IAH
Houston United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on
HP6338 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 20 minutes
- Flight Distance: 691 kms / 429 miles
Airline
- Amapola
- IATA: HP
- ICAO: APF
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/Chicago
- Arrival Timezone: America/Chicago
- Current Time in Midland: Saturday 2026-02-28 17:16 PM
- Current Time in Houston: Saturday 2026-02-28 17:16 PM
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|
AC4656 Air Canada |
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|
AC4658 Air Canada |
28/02/2026 17:31 |
1 hours 32 minutes 19:03 |
|
CM1565 Copa Airlines |
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|
EK6189 Emirates |
28/02/2026 14:56 |
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Amapola Flight HP6338 FAQs
What is the scheduled flight duration for Amapola HP6338 flight?
On average, nonstop flight takes 1 hour(s) 20 minutes, with the flight distance of 691 km (429 miles).
