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Amapola HP6258 Flight Status Today
Domestic flight Amapola HP6258 takes off from Houston (IAH) United States to Cleveland (CLE) United States. It's operated by Amapola. The plane leaves George Bush Intercontinental Airport at 10:45 America/Chicago. The flight is expected to land at Cleveland Hopkins International Airport at 14:11 America/New_York. The flight will last about 2 hours 26 minutes.
HP6258 - APF6258
Amapola (HP)
IAH
Houston United States
CLE
Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on
HP6258 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 26 minutes
- Flight Distance: 1757 kms / 1092 miles
Airline
- Amapola
- IATA: HP
- ICAO: APF
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Houston: Wednesday 2026-01-21 16:16 PM
- Current Time in Cleveland: Wednesday 2026-01-21 17:16 PM
Flight routes similar to Amapola HP6258
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
UA544 United Airlines |
21/01/2026 07:20 |
2 hours 34 minutes 11:08 |
|
|
UA1934 United Airlines |
21/01/2026 18:08 |
2 hours 50 minutes 21:58 |
|
NZ6413 Air New Zealand |
21/01/2026 07:20 |
2 hours 48 minutes 11:08 |
|
|
NZ6410 Air New Zealand |
21/01/2026 18:08 |
2 hours 50 minutes 21:58 |
|
|
NZ6414 Air New Zealand |
21/01/2026 13:43 |
2 hours 50 minutes 17:33 |
|
|
NZ6411 Air New Zealand |
21/01/2026 12:25 |
2 hours 51 minutes 16:16 |
|
|
NZ6412 Air New Zealand |
21/01/2026 18:50 |
2 hours 48 minutes 22:38 |
|
F94050 Frontier Airlines |
21/01/2026 19:26 |
2 hours 46 minutes 23:12 |
Amapola Flight HP6258 FAQs
What is the scheduled flight duration for Amapola HP6258 flight?
On average, nonstop flight takes 2 hour(s) 26 minutes, with the flight distance of 1757 km (1092 miles).