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Amapola HP6224 Flight Status Today
Domestic flight Amapola HP6224 takes off from Oklahoma City (OKC) United States to Houston (IAH) United States. It's operated by Amapola. The plane leaves Will Rogers World Airport at 12:34 America/Chicago. The flight is expected to land at George Bush Intercontinental Airport at 14:05 America/Chicago. The flight will last about 1 hours 31 minutes.
HP6224 - APF6224
Amapola (HP)
OKC
Oklahoma City United States
IAH
Houston United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on
HP6224 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 31 minutes
- Flight Distance: 636 kms / 395 miles
Airline
- Amapola
- IATA: HP
- ICAO: APF
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/Chicago
- Arrival Timezone: America/Chicago
- Current Time in Oklahoma City: Monday 2025-12-29 21:48 PM
- Current Time in Houston: Monday 2025-12-29 21:48 PM
Flight routes similar to Amapola HP6224
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
YV6216 Mesa Airlines |
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|
UA5531 United Airlines |
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|
NZ6811 Air New Zealand |
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|
NH7531 ANA |
29/12/2025 07:00 |
1 hours 29 minutes 08:48 |
|
|
UA6216 United Airlines |
29/12/2025 05:00 |
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|
|
YV6114 Mesa Airlines |
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Amapola Flight HP6224 FAQs
What is the scheduled flight duration for Amapola HP6224 flight?
On average, nonstop flight takes 1 hour(s) 31 minutes, with the flight distance of 636 km (395 miles).