Amapola HP6218 Flight Status Today

International flight Amapola HP6218 takes off from Houston (IAH) United States to Acapulco (ACA) Mexico. It's operated by Amapola. The plane leaves George Bush Intercontinental Airport at 13:36 America/Chicago. The flight is expected to land at Acapulco International Airport at 16:13 America/Mexico_City. The flight will last about 2 hours 37 minutes.

HP6218 - APF6218 Amapola (HP)
IAH Houston United States
Flight IAH to ACA
ACA Acapulco Mexico
Contact Airlines It may not operate on the date requested
Departure George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 13:36
None None
Arrival Acapulco International Airport
IATA: ACAICAO: MMAA
Scheduled 16:13
None None
HP6218 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 37 minutes
  • Flight Distance: 1532 kms / 952 miles
Airline
  • Amapola
  • IATA: HP
  • ICAO: APF
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Mexico_City
  • Current Time in Houston: Monday 2025-12-29 02:37 AM
  • Current Time in Acapulco: Monday 2025-12-29 02:37 AM

Flight routes similar to Amapola HP6218

Airline Flight no Departure Arrival
SkyWest Airlines OO5318
SkyWest Airlines 		29/12/2025
09:56 		2 hours 38 minutes
12:45
United Airlines UA5318
United Airlines 		29/12/2025
09:56 		2 hours 4 minutes
12:45

Amapola Flight HP6218 FAQs

What is the scheduled flight duration for Amapola HP6218 flight?

On average, nonstop flight takes 2 hour(s) 37 minutes, with the flight distance of 1532 km (952 miles).

How many Amapola HP6218 flights are operated a week?

7 flights per week. The Flight Amapola HP6218 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .