Amapola HP6095 Flight Status Today

Domestic flight Amapola HP6095 takes off from Columbus (CMH) United States to Houston (IAH) United States. It's operated by Amapola. The plane leaves John Glenn Columbus International Airport at 09:00 America/New_York. The flight is expected to land at George Bush Intercontinental Airport at 10:46 America/Chicago. The flight will last about 2 hours 46 minutes.

HP6095 - APF6095 Amapola (HP)
CMH Columbus United States
Flight CMH to IAH
IAH Houston United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 09:00
None None
Arrival George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 10:46
None None
HP6095 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 46 minutes
  • Flight Distance: 1587 kms / 986 miles
Airline
  • Amapola
  • IATA: HP
  • ICAO: APF
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Columbus: Saturday 2026-02-28 17:02 PM
  • Current Time in Houston: Saturday 2026-02-28 16:02 PM

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Amapola Flight HP6095 FAQs

What is the scheduled flight duration for Amapola HP6095 flight?

On average, nonstop flight takes 2 hour(s) 46 minutes, with the flight distance of 1587 km (986 miles).