Amapola HP6089 Flight Status Today

Domestic flight Amapola HP6089 takes off from Oklahoma City (OKC) United States to Houston (IAH) United States. It's operated by Amapola. The plane leaves Will Rogers World Airport at 07:15 America/Chicago. The flight is expected to land at George Bush Intercontinental Airport at 08:28 America/Chicago. The flight will last about 1 hours 13 minutes.

HP6089 - APF6089 Amapola (HP)
OKC Oklahoma City United States
Flight OKC to IAH
IAH Houston United States
Contact Airlines It may not operate on the date requested
Departure Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 07:15
None None
Arrival George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 08:28
None None
HP6089 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 13 minutes
  • Flight Distance: 636 kms / 395 miles
Airline
  • Amapola
  • IATA: HP
  • ICAO: APF
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Oklahoma City: Sunday 2026-01-18 16:44 PM
  • Current Time in Houston: Sunday 2026-01-18 16:44 PM

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Amapola Flight HP6089 FAQs

What is the scheduled flight duration for Amapola HP6089 flight?

On average, nonstop flight takes 1 hour(s) 13 minutes, with the flight distance of 636 km (395 miles).

How many Amapola HP6089 flights are operated a week?

1 flights per week. The Flight Amapola HP6089 is operated on Monday.