Amapola HP6085 Flight Status Today

Domestic flight Amapola HP6085 takes off from Houston (IAH) United States to Oklahoma City (OKC) United States. It's operated by Amapola. The plane leaves George Bush Intercontinental Airport at 18:16 America/Chicago. The flight is expected to land at Will Rogers World Airport at 19:51 America/Chicago. The flight will last about 1 hours 35 minutes.

HP6085 - APF6085 Amapola (HP)
IAH Houston United States
Flight IAH to OKC
OKC Oklahoma City United States
Contact Airlines It may not operate on the date requested
Departure George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 18:16
None None
Arrival Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 19:51
None None
HP6085 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 636 kms / 395 miles
Airline
  • Amapola
  • IATA: HP
  • ICAO: APF
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Houston: Monday 2026-02-09 18:33 PM
  • Current Time in Oklahoma City: Monday 2026-02-09 18:33 PM

Flight routes similar to Amapola HP6085

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Air New Zealand NZ6807
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Air New Zealand NZ6804
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United Airlines UA5334
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Copa Airlines CM1637
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SkyWest Airlines OO5278
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18:19

Amapola Flight HP6085 FAQs

What is the scheduled flight duration for Amapola HP6085 flight?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 636 km (395 miles).

How many Amapola HP6085 flights are operated a week?

7 flights per week. The Flight Amapola HP6085 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .