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Allegiant Air G4998 Flight Status Today
Domestic flight Allegiant Air G4998 takes off from Cedar Rapids (CID) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves The Eastern Iowa Airport at 18:35 19 January 2026 America/Chicago. The flight is expected to land at St. Petersburg-Clearwater International Airport at 22:11 19 January 2026 America/New_York. The flight will last about 2 hours 36 minutes.
Current status of G4998 is Scheduled On time Expected Depart in 15 hours, 49 minutes
G4998 - AAY998
Allegiant Air (G4)
CID
Cedar Rapids United States
PIE
Saint Petersburg United States
Scheduled On time
Expected Depart in 15 hours, 49 minutes
Scheduled
22:11 19 January 2026
None
None
G4998 Detail
- Type: Domestic Flight
- Flight Duration: 2 hours 36 minutes
- Flight Distance: 1753 kms / 1089 miles
Airline
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Saturday
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KCOI2
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Cedar Rapids: Monday 2026-01-19 02:46 AM
- Current Time in Saint Petersburg: Monday 2026-01-19 03:46 AM
Allegiant Air Flight G4998 FAQs
What is the scheduled flight duration for Allegiant Air G4998 flight?
On average, nonstop flight takes 2 hour(s) 36 minutes, with the flight distance of 1753 km (1089 miles).
What is the current status of Allegiant Air G4998 flight?
The current status of flight Allegiant Air G4998 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G4998 flight?
All Allegiant Air G4998 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G4998 flights are operated a week?
1 flights per week. The Flight Allegiant Air G4998 is operated on Saturday.