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Allegiant Air G4994 Flight Status Today
Domestic flight Allegiant Air G4994 takes off from Saint Petersburg (PIE) United States to Akron (CAK) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 07:00 America/New_York. The flight is expected to land at Akron-Canton Airport at 09:21 America/New_York. The flight will last about 2 hours 21 minutes.
- Type: Domestic Flight
- Flight Duration: 2 hours 21 minutes
- Flight Distance: 1447 kms / 899 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Thursday, Friday, Sunday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KCMH4
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Saturday 2026-03-21 04:23 AM
- Current Time in Akron: Saturday 2026-03-21 04:23 AM
Allegiant Air Flight G4994 FAQs
What is the scheduled flight duration for Allegiant Air G4994 flight?
On average, nonstop flight takes 2 hour(s) 21 minutes, with the flight distance of 1447 km (899 miles).
What type of aircraft is used for the Allegiant Air G4994 flight?
All Allegiant Air G4994 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G4994 flights are operated a week?
4 flights per week. The Flight Allegiant Air G4994 is operated on Monday, Thursday, Friday, Sunday.
