Allegiant Air G4994 Flight Status Today

Domestic flight Allegiant Air G4994 takes off from Saint Petersburg (PIE) United States to Middletown (MDT) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 06:40 America/New_York. The flight is expected to land at Harrisburg International Airport at 08:58 America/New_York. The flight will last about 2 hours 18 minutes.

G4994 - AAY994 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to MDT
MDT Middletown United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 06:40
None 9
Arrival Harrisburg International Airport
IATA: MDTICAO: KMDT
Scheduled 08:58
None B6
G4994 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 18 minutes
  • Flight Distance: 1468 kms / 912 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Thursday, Friday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KCMH4
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Thursday 2026-01-01 01:17 AM
  • Current Time in Middletown: Thursday 2026-01-01 01:17 AM

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Allegiant Air Flight G4994 FAQs

What is the scheduled flight duration for Allegiant Air G4994 flight?

On average, nonstop flight takes 2 hour(s) 18 minutes, with the flight distance of 1468 km (912 miles).

What type of aircraft is used for the Allegiant Air G4994 flight?

All Allegiant Air G4994 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G4994 flights are operated a week?

4 flights per week. The Flight Allegiant Air G4994 is operated on Monday, Thursday, Friday, Sunday.