Check your Flight status online
Allegiant Air G4994 Flight Status Today
Domestic flight Allegiant Air G4994 takes off from Saint Petersburg (PIE) United States to Akron (CAK) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 15:49 10 April 2026 America/New_York. The flight is expected to land at Akron-Canton Airport at 19:06 10 April 2026 America/New_York. The flight will last about 3 hours 17 minutes.
Current status of G4994 is Scheduled On time Estimated Depart in 2 hours, 21 minutes
- Type: Domestic Flight
- Flight Duration: 3 hours 17 minutes
- Flight Distance: 1447 kms / 899 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Thursday, Friday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KCMH4
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Friday 2026-04-10 13:28 PM
- Current Time in Akron: Friday 2026-04-10 13:28 PM
Allegiant Air Flight G4994 FAQs
What is the scheduled flight duration for Allegiant Air G4994 flight?
On average, nonstop flight takes 3 hour(s) 17 minutes, with the flight distance of 1447 km (899 miles).
What is the current status of Allegiant Air G4994 flight?
The current status of flight Allegiant Air G4994 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G4994 flight?
All Allegiant Air G4994 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G4994 flights are operated a week?
4 flights per week. The Flight Allegiant Air G4994 is operated on Monday, Thursday, Friday, Sunday.
