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Allegiant Air G4983 Flight Status Today
Domestic flight Allegiant Air G4983 takes off from Saint Petersburg (PIE) United States to Bloomington (BMI) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 17:32 09 February 2026 America/New_York. The flight is expected to land at Central Illinois Regional Airport at 19:08 09 February 2026 America/Chicago. The flight will last about 2 hours 36 minutes.
Current status of G4983 is Scheduled On time Expected Depart in 1 hour, 56 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 36 minutes
- Flight Distance: 1507 kms / 936 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Thursday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Airbus A320 (sharklets)
- Callsign: F-KBOW3
- Departure Timezone: America/New_York
- Arrival Timezone: America/Chicago
- Current Time in Saint Petersburg: Monday 2026-02-09 15:36 PM
- Current Time in Bloomington: Monday 2026-02-09 14:36 PM
Flight routes similar to Allegiant Air G4983
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G42676 Allegiant Air |
09/02/2026 17:19 |
2 hours 27 minutes 18:46 |
Allegiant Air Flight G4983 FAQs
What is the scheduled flight duration for Allegiant Air G4983 flight?
On average, nonstop flight takes 2 hour(s) 36 minutes, with the flight distance of 1507 km (936 miles).
What is the current status of Allegiant Air G4983 flight?
The current status of flight Allegiant Air G4983 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G4983 flight?
All Allegiant Air G4983 flights are operated using Airbus A320 (sharklets) aircraft.
How many Allegiant Air G4983 flights are operated a week?
2 flights per week. The Flight Allegiant Air G4983 is operated on Thursday, Sunday.
