Allegiant Air G4983 Flight Status Today

Domestic flight Allegiant Air G4983 takes off from Asheville (AVL) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Asheville Regional Airport at 15:20 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 16:58 America/New_York. The flight will last about 1 hours 38 minutes.

G4983 - AAY983 Allegiant Air (G4)
AVL Asheville United States
Flight AVL to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 15:20
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 16:58
None 9
G4983 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 38 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KBOW3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Asheville: Tuesday 2025-12-30 14:24 PM
  • Current Time in Saint Petersburg: Tuesday 2025-12-30 14:24 PM

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Allegiant Air Flight G4983 FAQs

What is the scheduled flight duration for Allegiant Air G4983 flight?

On average, nonstop flight takes 1 hour(s) 38 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G4983 flight?

All Allegiant Air G4983 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G4983 flights are operated a week?

2 flights per week. The Flight Allegiant Air G4983 is operated on Thursday, Sunday.