Allegiant Air G4983 Flight Status Today

Domestic flight Allegiant Air G4983 takes off from Saint Petersburg (PIE) United States to Bloomington (BMI) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 17:32 America/New_York. The flight is expected to land at Central Illinois Regional Airport at 19:08 America/Chicago. The flight will last about 2 hours 36 minutes.

G4983 - AAY983 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to BMI
BMI Bloomington United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 17:32
None 3
Arrival Central Illinois Regional Airport
IATA: BMIICAO: KBMI
Scheduled 19:08
None None
G4983 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 36 minutes
  • Flight Distance: 1507 kms / 936 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-KBOW3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Saint Petersburg: Tuesday 2026-01-20 06:45 AM
  • Current Time in Bloomington: Tuesday 2026-01-20 05:45 AM

Flight routes similar to Allegiant Air G4983

Airline Flight no Departure Arrival
Allegiant Air G42676
Allegiant Air 		20/01/2026
17:19 		2 hours 27 minutes
18:46

Allegiant Air Flight G4983 FAQs

What is the scheduled flight duration for Allegiant Air G4983 flight?

On average, nonstop flight takes 2 hour(s) 36 minutes, with the flight distance of 1507 km (936 miles).

What type of aircraft is used for the Allegiant Air G4983 flight?

All Allegiant Air G4983 flights are operated using Airbus A319 aircraft.

How many Allegiant Air G4983 flights are operated a week?

2 flights per week. The Flight Allegiant Air G4983 is operated on Thursday, Sunday.