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Allegiant Air G4980 Flight Status Today
Domestic flight Allegiant Air G4980 takes off from Saint Petersburg (PIE) United States to Newburgh (SWF) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 07:10 18 January 2026 America/New_York. The flight is expected to land at Stewart International Airport at 09:58 18 January 2026 America/New_York. The flight will last about 2 hours 48 minutes.
Current status of G4980 is Departed On time Estimated Arrival in 1 hour, 32 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 48 minutes
- Flight Distance: 1698 kms / 1055 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KTPA2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Saint Petersburg: Sunday 2026-01-18 08:01 AM
- Current Time in Newburgh: Sunday 2026-01-18 08:01 AM
Allegiant Air Flight G4980 FAQs
What is the scheduled flight duration for Allegiant Air G4980 flight?
On average, nonstop flight takes 2 hour(s) 48 minutes, with the flight distance of 1698 km (1055 miles).
What is the current status of Allegiant Air G4980 flight?
The current status of flight Allegiant Air G4980 is Departed On time.
What type of aircraft is used for the Allegiant Air G4980 flight?
All Allegiant Air G4980 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G4980 flights are operated a week?
1 flights per week. The Flight Allegiant Air G4980 is operated on Sunday.
