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Allegiant Air G4974 Flight Status Today
Domestic flight Allegiant Air G4974 takes off from Richmond (RIC) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Richmond International Airport (Byrd Field) at 07:30 22 March 2026 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 10:30 22 March 2026 America/New_York. The flight will last about 2 hours 13 minutes.
Current status of G4974 is Scheduled On time Expected Depart in 4 hours, 14 minutes
- Type: Domestic Flight
- Flight Duration: 2 hours 13 minutes
- Flight Distance: 1177 kms / 731 miles
- Allegiant Air
- IATA: G4
- ICAO: AAY
- Operating Days: Monday, Wednesday, Friday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: F-KTLH2
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Richmond: Sunday 2026-03-22 03:16 AM
- Current Time in Saint Petersburg: Sunday 2026-03-22 03:16 AM
Allegiant Air Flight G4974 FAQs
What is the scheduled flight duration for Allegiant Air G4974 flight?
On average, nonstop flight takes 2 hour(s) 13 minutes, with the flight distance of 1177 km (731 miles).
What is the current status of Allegiant Air G4974 flight?
The current status of flight Allegiant Air G4974 is Scheduled On time.
What type of aircraft is used for the Allegiant Air G4974 flight?
All Allegiant Air G4974 flights are operated using Boeing 737MAX 8 Passenger aircraft.
How many Allegiant Air G4974 flights are operated a week?
3 flights per week. The Flight Allegiant Air G4974 is operated on Monday, Wednesday, Friday.
