Allegiant Air G4974 Flight Status Today

Domestic flight Allegiant Air G4974 takes off from Albany (ALB) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Albany International Airport at 09:37 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at 13:07 America/New_York. The flight will last about 3 hours 2 minutes.

G4974 - AAY974 Allegiant Air (G4)
ALB Albany United States
Flight ALB to PIE
PIE Saint Petersburg United States
Contact Airlines It may not operate on the date requested
Departure Albany International Airport
IATA: ALBICAO: KALB
Scheduled 09:37
None A1
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 13:07
None 3
G4974 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 2 minutes
  • Flight Distance: 1831 kms / 1138 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Monday, Wednesday, Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319
  • Callsign: F-KTLH2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Albany: Sunday 2026-02-08 20:43 PM
  • Current Time in Saint Petersburg: Sunday 2026-02-08 20:43 PM

Flight routes similar to Allegiant Air G4974

Airline Flight no Departure Arrival
Allegiant Air G43667
Allegiant Air 		08/02/2026
20:00 		3 hours 4 minutes
23:04

Allegiant Air Flight G4974 FAQs

What is the scheduled flight duration for Allegiant Air G4974 flight?

On average, nonstop flight takes 3 hour(s) 2 minutes, with the flight distance of 1831 km (1138 miles).

What type of aircraft is used for the Allegiant Air G4974 flight?

All Allegiant Air G4974 flights are operated using Airbus A319 aircraft.

How many Allegiant Air G4974 flights are operated a week?

3 flights per week. The Flight Allegiant Air G4974 is operated on Monday, Wednesday, Friday.