Allegiant Air G49339 Flight Status Today

Domestic flight Allegiant Air G49339 takes off from Middletown (MDT) United States to Saint Petersburg (PIE) United States. It's operated by Allegiant Air. The plane leaves Harrisburg International Airport at 17:05 America/New_York. The flight is expected to land at St. Petersburg-Clearwater International Airport at None America/New_York. The flight will last about 2 hours 58 minutes.

G49339 - AAY9339 Allegiant Air (G4)
MDT Middletown United States
Flight MDT to PIE
PIE Saint Petersburg United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Harrisburg International Airport
IATA: MDTICAO: KMDT
Scheduled 17:05
None None
Arrival St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled None
None None
G49339 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 58 minutes
  • Flight Distance: 1468 kms / 912 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320-214
  • Callsign: AAY9339
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Middletown: Tuesday 2026-01-20 02:40 AM
  • Current Time in Saint Petersburg: Tuesday 2026-01-20 02:40 AM

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None
22:44

Allegiant Air Flight G49339 FAQs

What is the scheduled flight duration for Allegiant Air G49339 flight?

On average, nonstop flight takes 2 hour(s) 58 minutes, with the flight distance of 1468 km (912 miles).

What type of aircraft is used for the Allegiant Air G49339 flight?

All Allegiant Air G49339 flights are operated using Airbus A320-214 aircraft.